Question

What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that apply.

y = −Two-fifthsx − 1
2x + 5y = −5
y = −Two-fifthsx − 3
2x + 5y = −15
y − 1= −Two-fifths(x + 5)

Answer 1

The given line has slope −2/5 (2x+5y=10 → y = −(2/5)x + 2). A parallel line through (−5,1) has equation y = −(2/5)x − 1 (since 1 = −(2/5)(−5) + b → b = −1).

So the correct choices are:
- y = −Two-fifthsx − 1
- 2x + 5y = −5 (same line in standard form)
- y − 1 = −Two-fifths(x + 5) (point‑slope form)

The other two choices correspond to y = −(2/5)x − 3 and are not correct.