Asked by Taylor
Chemical analysis of a gas shows that it contains one carbon atom for every one hydrogen atom. The densiry ofthis gas is 1.161 g/l at STP. What is the minimus oxygen volume needed at STP for the complete combustion of .500 mol of this gas?
Answers
Answered by
DrBob222
density of 1.161 g/L x 22.4 L/mol@ATP = 26 for the mass of 1 mole or the molar mass of 26. The molecular formula must be C2H2.
2C2H2 + 5O2 ==> 4CO2 + 2H2O
0.5 mol C2H2 x (5 moles O2/2 moles C2H2) = ?? moles oxygen needed.
At STP, each mole oxygen occupies 22.4 L.
2C2H2 + 5O2 ==> 4CO2 + 2H2O
0.5 mol C2H2 x (5 moles O2/2 moles C2H2) = ?? moles oxygen needed.
At STP, each mole oxygen occupies 22.4 L.
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