Asked by Katy

What is the percent aluminum in a sample weighing 1.85 grams. If 35 mL of wet hydrogen gas was produced @ 24 degrees Celsius under a total pressure of 752 torr?

Answers

Answered by DrBob222
2Al + 6H^+ ==>2Al^+3 + 3H2
Use PV = nRT to calculate moles DRY hydrogen produced.
Convert mole dry H2 to moles Al, then to grams Al.
Then %Al = (mass Al/mass sample)*100 = ??
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