Asked by sh
Samuel is trying to hear what is being said on the other side of the door, but the sound of the voices has to pass through a thin door. The sound travels at a velocity of 343 m/s through air, and 560 m/s through the door. The following questions address the frequency and wavelength of the man's voice traveling through air compared to it traveling through the door.
Choose the statement below that BEST describes what happens to the frequency in this scenario.
(1 point)
Responses
The frequency of the voice sound wave traveling through the air is faster than when it travels through the door.
The frequency of the voice sound wave traveling through the air is faster than when it travels through the door.
The frequency of the voice sound wave traveling through the air is slower than when it travels through the door.
The frequency of the voice sound wave traveling through the air is slower than when it travels through the door.
The frequency of the voice sound wave traveling through the air is the same as when it travels through the door.
The frequency of the voice sound wave traveling through the air is the same as when it travels through the door.
The frequency of the voice sound wave changes with the distance the speaker is from the door. It decreases as it travels across the air in the room. .
The frequency of the voice sound wave changes with the distance the speaker is from the door. It decreases as it travels across the air in the room. .
Question 2
The man in the red shirt has a voice frequency of 100 Hz. Mathematically, how does the wavelength compare as the voice travels through the air, versus through the door. (1 point)
Responses
The wavelength is longer in the air than it is in the door
The wavelength is longer in the air than it is in the door
The wavelength is the same in the air and in the door.
The wavelength is the same in the air and in the door.
Not enough information is provided to solve.
Not enough information is provided to solve.
The wavelength is longer in the door than in the air
The wavelength is longer in the door than in the air
All Answers 1
Answered by
GPT-5 mini
AI
Q1: The frequency of the voice sound wave traveling through the air is the same as when it travels through the door.
Reason: Frequency is set by the source and does not change when a wave passes into a new medium.
Q2: The wavelength is longer in the door than in the air.
Reason and math: λ = v/f. In air λ_air = 343 m/s ÷ 100 Hz = 3.43 m. In the door λ_door = 560 m/s ÷ 100 Hz = 5.60 m, so the door wavelength is longer.
Reason: Frequency is set by the source and does not change when a wave passes into a new medium.
Q2: The wavelength is longer in the door than in the air.
Reason and math: λ = v/f. In air λ_air = 343 m/s ÷ 100 Hz = 3.43 m. In the door λ_door = 560 m/s ÷ 100 Hz = 5.60 m, so the door wavelength is longer.
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