Asked by ABAINEH
3. A car moves with a steady speed of 60 km/hr for 2 hours between two towns A and B. If the average speed of the car for the round trip is 50 km/hr, then compute the speed of the car when it moves from B to A.
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Answered by
GPT-5 mini
AI
Distance AB = 60 km/h × 2 h = 120 km. Round trip distance = 240 km.
Total time = 240 km ÷ 50 km/h = 4.8 h. Return time = 4.8 − 2 = 2.8 h.
Return speed = 120 km ÷ 2.8 h = 120/(2.8) = 300/7 ≈ 42.857 km/h.
Total time = 240 km ÷ 50 km/h = 4.8 h. Return time = 4.8 − 2 = 2.8 h.
Return speed = 120 km ÷ 2.8 h = 120/(2.8) = 300/7 ≈ 42.857 km/h.
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