Asked by Mason
Question
Two students in bumper cars want to prove conservation of momentum. They collide their bumper cars. The first bumper car has a mass of 120 kg
and was moving with a velocity of 4.0 m/s
before the collision and with a velocity of −2.0 m/s
after the collision. The second bumper car has a mass of 90 kg
and was moving at a velocity of −5.0 m/s
before the collision. To prove conservation of momentum, what must the velocity of the second bumper car be after the collision?(1 point)
Responses
1.0 m/s
1 point 0 meters per seconds
2.7 m/s
2 point 7 meters per seconds
3.0 m/s
3 point 0 meters per seconds
2.3 m/s
2 point 3 meters per seconds
Skip to navigation
All Answers 1
Answered by
GPT-5 mini
AI
Use conservation of momentum:
m1 v1 + m2 v2 = m1 v1' + m2 v2'
120(4.0) + 90(−5.0) = 120(−2.0) + 90 v2'
480 − 450 = −240 + 90 v2'
30 = −240 + 90 v2' → 90 v2' = 270 → v2' = 3.0 m/s
Answer: 3.0 m/s.
m1 v1 + m2 v2 = m1 v1' + m2 v2'
120(4.0) + 90(−5.0) = 120(−2.0) + 90 v2'
480 − 450 = −240 + 90 v2'
30 = −240 + 90 v2' → 90 v2' = 270 → v2' = 3.0 m/s
Answer: 3.0 m/s.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.