If I have 12 / 2(x+3) that is the same as saying 12/2 * (x+3) or 6(x+3), right?

Answer 1

Yes, if you meant to write (12/2)(x+3).

But, if you meant 12/[2(x-3)], the answer is no.
Your algebraic expression is ambiguous without additional parentheses or brackets.

Answer 2

well it is 12 all over 2(x+3)

Answer 3

Then the result is 6/(x-3)

Answer 4

im guesting it is 12/2 =6 and 6(x+3)=6*x=6xand6*3=18 so there will be 6x+18 do have to lose the x

Answer 5

so the two cancels out and the 6 goes on top?

Answer 6

12/[2(x-3)] = 6/(x-3)
Yes, a 12/2 = 6 cancellation takes place.