Question

What is the surface area of a square pyramid if the base edge = 68 in. and the slant height = 125 in.?(1 point)
Responses

32,625 in2

32,625 in squared

21,624 in2

21,624 in squared

17,000 in2

17,000 in squared

17,068 in2

Answer 1

Surface area = base area + lateral area = s^2 + (1/2)(perimeter)(slant height).
Here s = 68, perimeter = 4·68 = 272, l = 125.

Base = 68^2 = 4,624 in^2.
Lateral = (1/2)(272)(125) = 17,000 in^2.
Total = 4,624 + 17,000 = 21,624 in^2.

Answer: 21,624 in^2.