Question

Find the surface area of a rectangular pyramid with these measurements: l
= 5.5 yd., w
= 4 yd., and h
= 6 yd. (1 point)
Responses

255.06 yd.2

255 point 0 6 yards squared

83.19 yd.2

83 point 1 9 yards squared

242.27 yd.2

242 point 2 7 yards squared

56.79 yd.2

Answer 1

Surface area = base area + lateral area.
Base = l·w = 5.5·4 = 22 yd^2.

Slant heights:
s_l (for sides of length l) = sqrt(h^2 + (w/2)^2) = sqrt(36 + 2^2) = sqrt(40) ≈ 6.3249 yd
s_w (for sides of length w) = sqrt(h^2 + (l/2)^2) = sqrt(36 + 2.75^2) = sqrt(43.5625) ≈ 6.6002 yd

Lateral area = l·s_l + w·s_w ≈ 5.5·6.3249 + 4·6.6002 ≈ 61.19 yd^2

Total surface area ≈ 22 + 61.19 = 83.19 yd^2.

Answer: 83.19 yd^2.