Question

What is the nuclear binding energy of an atom that has a mass defect of 1.643 mc030-1.jpg 10–28 kg?
Use E = mc2. (Remember: The speed of light is approximately 3.00 mc030-2.jpg 108 m/s.)
1.83 mc030-3.jpg 10–46 J
4.93 mc030-4.jpg 10–20 J
1.48 mc030-5.jpg 10–11 J
5.48 mc030-6.jpg 1045 J

Answer 1

E = mc^2 = (1.643 × 10^−28 kg) × (3.00 × 10^8 m/s)^2
= 1.643 × 10^−28 × 9.00 × 10^16 J
= 1.4787 × 10^−11 J ≈ 1.48 × 10^−11 J.

So the correct choice is 1.48 × 10^−11 J.