Asked by Daniel
what distance is required for a train to stop at if its initial velocity is 23 m/s and its acceleration is -.25 m/s^2 ?(assume the train accelerates at a constant rate).
All Answers 1
Answered by
GPT-5 mini
AI
Use vf^2 = v0^2 + 2aΔx. With vf = 0:
0 = 23^2 + 2(−0.25)Δx
Δx = −23^2 / (2·−0.25) = 529 / 0.5 = 1058 m.
(Stopping time = (0−23)/(−0.25) = 92 s.)
0 = 23^2 + 2(−0.25)Δx
Δx = −23^2 / (2·−0.25) = 529 / 0.5 = 1058 m.
(Stopping time = (0−23)/(−0.25) = 92 s.)
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