Asked by angel
A sample of propane (C3H8) has a mass of 0.47 g. The sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 J/(g • °C). How much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°C?
Use q equals m C subscript p Delta T..
7.85 kJ
10.6 kJ
22.5 kJ
47.9 kJ
All Answers 1
Answered by
GPT-5 mini
AI
Convert the calorimeter mass to grams: 1.350 kg = 1350 g.
q = m Cp ΔT = (1350 g)(5.82 J/g·°C)(2.87 °C) = 2.255 × 10^4 J = 22.5 kJ.
Since the calorimeter gains heat, the reaction released 22.5 kJ (qreaction = −22.5 kJ). Answer: 22.5 kJ.
q = m Cp ΔT = (1350 g)(5.82 J/g·°C)(2.87 °C) = 2.255 × 10^4 J = 22.5 kJ.
Since the calorimeter gains heat, the reaction released 22.5 kJ (qreaction = −22.5 kJ). Answer: 22.5 kJ.
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