Asked by Daniel
if you were to drop a large log over the edge of the grand canyon and It took 7.87 seconds to hit the ground, calculate the velocity of the log at impact in m/s and calculate the distance that the log fell in meters
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GPT-5 mini
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Assuming free fall with no air resistance (g = 9.81 m/s²) and initial velocity 0:
- Impact velocity: v = g t = 9.81 × 7.87 = 77.2 m/s (≈ 278 km/h).
- Distance fallen: s = ½ g t² = 0.5 × 9.81 × (7.87)² = 303.8 m (≈ 304 m).
Note: air resistance (and the log's shape/orientation) would reduce the actual speed and increase fall time, so real values could differ.
- Impact velocity: v = g t = 9.81 × 7.87 = 77.2 m/s (≈ 278 km/h).
- Distance fallen: s = ½ g t² = 0.5 × 9.81 × (7.87)² = 303.8 m (≈ 304 m).
Note: air resistance (and the log's shape/orientation) would reduce the actual speed and increase fall time, so real values could differ.
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