Question

a paintball shot form a paintball gun with an initial velocity of 45 m/s. if the pint ball accelerates at a uniform rate of 1.5 m/s^2 over a distance of 35 meters, what is the paintball's final vellocity

Answer 1

Use v^2 = u^2 + 2as.

u = 45.0 m/s, a = 1.5 m/s^2, s = 35 m:

v^2 = 45^2 + 2(1.5)(35) = 2025 + 105 = 2130
v = sqrt(2130) ≈ 46.15 m/s

(≈46.2 m/s, in the same direction as the initial velocity.)