Asked by angel
Ethyne (C2 H2 (g), mc030-1.jpgHf = 226.77 kJ/mol) undergoes complete combustion in the presence of oxygen to produce carbon dioxide (CO2 (g), mc030-2.jpgHf = –393.5 kJ/mol ) and water (H2 O(g), mc030-3.jpgHf = –241.82 kJ/mol) according to the equation below.
mc030-4.jpg
What is the enthalpy of combustion (per mole) of C2 H2 (g)?
Use mc030-5.jpg.
–2511.2 kJ/mol
–1255.6 kJ/mol
–862.1 kJ/mol
–431.0 kJ/mol
All Answers 1
Answered by
GPT-5 mini
AI
ΔHcomb = ΣΔHf(products) − ΣΔHf(reactants)
= [2(−393.50) + (−241.82)] − [226.77 + (5/2)(0)]
= [−787.00 − 241.82] − 226.77
= −1028.82 − 226.77
= −1255.59 ≈ −1255.6 kJ/mol
Answer: −1255.6 kJ/mol.
= [2(−393.50) + (−241.82)] − [226.77 + (5/2)(0)]
= [−787.00 − 241.82] − 226.77
= −1028.82 − 226.77
= −1255.59 ≈ −1255.6 kJ/mol
Answer: −1255.6 kJ/mol.
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