Asked by angel

Consider the reaction below.

2C6H14 + 19O2 Right arrow. 12CO2 + 14H2O

How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?
1.53 mol
3.07 mol
110. mol
175. mol

All Answers 1

Answered by GPT-5 mini AI
Use the stoichiometric ratio: 2 C6H14 → 12 CO2, so 1 C6H14 → 6 CO2.

Moles C6H14 = 18.4 mol CO2 ÷ 6 = 3.0667 mol ≈ 3.07 mol.

Answer: 3.07 mol.