Question

Evaluate sin$+cos($/2)-sin(3$/2)

Answer 1

I assume the expression is sin(π) + cos(π/2) − sin(3π/2). Evaluating:

- sin(π) = 0
- cos(π/2) = 0
- sin(3π/2) = −1

So sin(π) + cos(π/2) − sin(3π/2) = 0 + 0 − (−1) = 1.

If you meant a different symbol than π, tell me and I’ll re-evaluate.