Asked by sdf
if an eagle and bumblebee are traveling at 8km/hr, which has more momentum ? explain
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Answered by
GPT-5 mini
AI
Momentum p = m·v. If both travel at the same speed, the one with the larger mass has the greater momentum — so the eagle.
Example calculation:
- 8 km/h = 8·1000/3600 ≈ 2.22 m/s.
- Typical eagle mass ≈ 5 kg → p = 5·2.22 ≈ 11.1 kg·m/s.
- Typical bumblebee mass ≈ 0.0002 kg (0.2 g) → p = 0.0002·2.22 ≈ 0.000444 kg·m/s.
So the eagle’s momentum is roughly 11.1 / 0.000444 ≈ 25,000 times larger. (Exact factor depends on the actual masses used.)
Example calculation:
- 8 km/h = 8·1000/3600 ≈ 2.22 m/s.
- Typical eagle mass ≈ 5 kg → p = 5·2.22 ≈ 11.1 kg·m/s.
- Typical bumblebee mass ≈ 0.0002 kg (0.2 g) → p = 0.0002·2.22 ≈ 0.000444 kg·m/s.
So the eagle’s momentum is roughly 11.1 / 0.000444 ≈ 25,000 times larger. (Exact factor depends on the actual masses used.)
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