Question

Eliminate $ from
X=4sin$, Y=3cos$

Answer 1

Interpreting the problem as x = 4 sin θ, y = 3 cos θ, eliminate θ:

sin θ = x/4, cos θ = y/3, so
(x/4)^2 + (y/3)^2 = sin^2θ + cos^2θ = 1.

Thus the Cartesian equation is x^2/16 + y^2/9 = 1 — an ellipse centered at the origin with semi-axes 4 and 3.