Asked by ggg
Calculate the first and second velocities of the car with three washers attached to the pulley, using the formulas
v1 = 0.25 m / t1, and
v2 = 0.25 m / (t2 – t1)
where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.
What is the first velocity of the car with three washers at the 0.25 meter mark?
m/s
What is the second velocity of the car with three washers at the 0.50 meter mark?
m/s
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have your measured times t1 and t2. Please give the average times (in seconds) the car took to reach 0.25 m (t1) and 0.50 m (t2). Then I will compute:
- v1 = 0.25 / t1 (m/s)
- v2 = 0.25 / (t2 − t1) (m/s)
Both answers will be rounded to two decimals.
Example: if t1 = 0.80 s and t2 = 1.45 s then
- v1 = 0.25 / 0.80 = 0.3125 → 0.31 m/s
- v2 = 0.25 / (1.45 − 0.80) = 0.25 / 0.65 = 0.384615 → 0.38 m/s
Give me your t1 and t2 and I’ll compute the precise v1 and v2.
- v1 = 0.25 / t1 (m/s)
- v2 = 0.25 / (t2 − t1) (m/s)
Both answers will be rounded to two decimals.
Example: if t1 = 0.80 s and t2 = 1.45 s then
- v1 = 0.25 / 0.80 = 0.3125 → 0.31 m/s
- v2 = 0.25 / (1.45 − 0.80) = 0.25 / 0.65 = 0.384615 → 0.38 m/s
Give me your t1 and t2 and I’ll compute the precise v1 and v2.
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