Question

in game 1 emerson struck out 30 times in 90 times at bat. in game 2, he struck out 40 times in 120 times at bat. in game 3 emerson struck out 42 times in 140 times at bat. what percentage of times at bat did emerson acually hit the ball and how do u get that answer

Answer 1

68%

Answer 2

Step 1: For each game, subtract strikeouts from at-bats to get times he actually put the ball in play:
- Game 1: 90 − 30 = 60
- Game 2: 120 − 40 = 80
- Game 3: 140 − 42 = 98

Step 2: Convert to percentages (hits ÷ at-bats × 100):
- Game 1: 60/90 = 2/3 = 66.666...% (≈ 66.7%)
- Game 2: 80/120 = 2/3 = 66.666...% (≈ 66.7%)
- Game 3: 98/140 = 0.70 = 70%

Overall combined:
- Total at-bats = 90 + 120 + 140 = 350
- Total non-strikeouts = 60 + 80 + 98 = 238
- Percentage = 238/350 = 0.68 = 68%

So overall Emerson put the ball in play 68% of the time.