Question

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Step 1: Original equation Assuming the points W, L, T form a right-angled triangle with the right angle at L, the original equation is the Pythagorean theorem:\(WT^{2}=LW^{2}+TL^{2}\)Step 2: Substitute values Substitute the given values of \(WT=53\) and \(LW=45\) into the equation:\(53^{2}=45^{2}+TL^{2}\)Step 3: Solve for \(TL^{2}\) Calculate the squares and isolate \(TL^{2}\):\(2809=2025+TL^{2}\)\(TL^{2}=2809-2025\)\(TL^{2}=784\)Step 4: Find TL Take the square root of both sides to find the value of TL:\(TL=\sqrt{784}\)\(TL=28\)

Answer 1

Assuming triangle WLT is right-angled at L, use the Pythagorean theorem: WT^2 = LW^2 + TL^2. Substituting WT = 53 and LW = 45 gives 53^2 = 45^2 + TL^2, so 2809 = 2025 + TL^2 and TL^2 = 784, hence TL = √784 = 28.