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5% of batteries produced at a factory are defective. Use the binomial model to find the probability that 1 battery in a pack of 16 is defective.
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Let X ~ Binomial(n=16, p=0.05). Then
P(X = 1) = C(16,1)(0.05)^1(0.95)^15 = 16 · 0.05 · 0.95^15 ≈ 0.370633.
So about 0.3706 (37.06%).
P(X = 1) = C(16,1)(0.05)^1(0.95)^15 = 16 · 0.05 · 0.95^15 ≈ 0.370633.
So about 0.3706 (37.06%).
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