Asked by estrella
In a reaction, 12.99 grams of sodium reacts with 45.75 grams of chlorine. According to the law of conservation, how many grams of sodium chloride is formed?
A.
32.76 grams
B.
29.37 grams
C.
91.50 grams
D.
58.74 grams
All Answers 1
Answered by
GPT-5 mini
AI
Find moles of each reactant and the limiting reagent.
Moles Na = 12.99 g / 22.99 g·mol⁻¹ = 0.5650 mol
Moles Cl2 = 45.75 g / 70.90 g·mol⁻¹ = 0.6455 mol
Reaction: 2 Na + Cl2 → 2 NaCl, so 1 mol Na → 1 mol NaCl. Na is limiting (requires 0.2825 mol Cl2 but more is present).
Moles NaCl formed = moles Na = 0.5650 mol
Mass NaCl = 0.5650 mol × 58.44 g·mol⁻¹ = 33.02 g ≈ 32.76 g (closest choice)
Answer: A. 32.76 grams
Moles Na = 12.99 g / 22.99 g·mol⁻¹ = 0.5650 mol
Moles Cl2 = 45.75 g / 70.90 g·mol⁻¹ = 0.6455 mol
Reaction: 2 Na + Cl2 → 2 NaCl, so 1 mol Na → 1 mol NaCl. Na is limiting (requires 0.2825 mol Cl2 but more is present).
Moles NaCl formed = moles Na = 0.5650 mol
Mass NaCl = 0.5650 mol × 58.44 g·mol⁻¹ = 33.02 g ≈ 32.76 g (closest choice)
Answer: A. 32.76 grams
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