Question

n a hospital 24 operating rooms were sampled. The mean noise level was 41.6 decibels and the standard deviation was 7.5. What is the 95% confidence interval of the true mean of the noise levels in the operating rooms? If possible, can you list the steps you used. I'm having a hard time calculating these results. Thanks.

Answer 1

Formula:

CI95 = mean + or - 1.96(sd/√n)

Substituting your data:

CI95 = 41.6 + or - 1.96(7.5/√24)

Finish the calculations for your confidence interval.

Answer 2

Thank you very much for the clarification.