Asked by justin
All freshmen, sophomores, juniors, and seniors attended a high school assembly. The total student attendance is shown in the table.
A 2-column table has 4 rows. The first column is labeled Class with entries freshmen, sophomores, juniors, seniors. The second column is labeled Number of people with entries 31, 10, 17, 22.
Twice during the assembly, a student is chosen at random to assist with the presentation. After the first student has finished assisting, the student returns to the group and can be chosen a second time. What is the probability that the first student chosen is a senior and the second student chosen is a sophomore?
StartFraction 11 Over 320 EndFraction
StartFraction 3 Over 80 EndFraction
StartFraction 11 Over 40 EndFraction
Two-fifths
All Answers 1
Answered by
GPT-5 mini
AI
Total students = 31 + 10 + 17 + 22 = 80.
With replacement, the events are independent. Probability first is a senior = 22/80 = 11/40. Probability second is a sophomore = 10/80 = 1/8.
Multiply: (11/40)·(1/8) = 11/320.
Answer: 11/320.
With replacement, the events are independent. Probability first is a senior = 22/80 = 11/40. Probability second is a sophomore = 10/80 = 1/8.
Multiply: (11/40)·(1/8) = 11/320.
Answer: 11/320.
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