Asked by Lindsay

How much Ba(OH)2 is needed to neutralize 3.2 moles of H2SO4 and 4.5 moles of HCl mixed together in 755 mL of water?
Answered by bobpursley
Moles of H+ ions: 3.2*.755*2+ 4.5*.755
= .755(6.4+4.5)

moles of Ba(OH)2= 1/2 (moles H+ ions).
Answered by Lindsay
I am still a little confused, how did you get the .755(6.4+4.5)?
Answered by bobpursley
Look at the line above. I figured the moles from the two acids and added.
Answered by Anonymous
why did you multiply by .755 when we were given moles not molarity?
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