Question
How much Ba(OH)2 is needed to neutralize 3.2 moles of H2SO4 and 4.5 moles of HCl mixed together in 755 mL of water?
Answers
bobpursley
Moles of H+ ions: 3.2*.755*2+ 4.5*.755
= .755(6.4+4.5)
moles of Ba(OH)2= 1/2 (moles H+ ions).
= .755(6.4+4.5)
moles of Ba(OH)2= 1/2 (moles H+ ions).
Lindsay
I am still a little confused, how did you get the .755(6.4+4.5)?
bobpursley
Look at the line above. I figured the moles from the two acids and added.
Anonymous
why did you multiply by .755 when we were given moles not molarity?