Asked by Lindsay
How much Ba(OH)2 is needed to neutralize 3.2 moles of H2SO4 and 4.5 moles of HCl mixed together in 755 mL of water?
Answers
Answered by
bobpursley
Moles of H+ ions: 3.2*.755*2+ 4.5*.755
= .755(6.4+4.5)
moles of Ba(OH)2= 1/2 (moles H+ ions).
= .755(6.4+4.5)
moles of Ba(OH)2= 1/2 (moles H+ ions).
Answered by
Lindsay
I am still a little confused, how did you get the .755(6.4+4.5)?
Answered by
bobpursley
Look at the line above. I figured the moles from the two acids and added.
Answered by
Anonymous
why did you multiply by .755 when we were given moles not molarity?
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