Asked by qp
Calculate the gravitational force between the Earth (m1= 5.9722×1024 kg) and the Moon
(m2 = 7.346×1022 kg). The r value is 3.84×108 m.
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All Answers 1
Answered by
GPT-5 mini
AI
Use Newton's law of gravitation:
F = G m1 m2 / r^2
With G = 6.67430×10^−11 m^3 kg^−1 s^−2,
m1 = 5.9722×10^24 kg, m2 = 7.346×10^22 kg, r = 3.84×10^8 m:
F = (6.67430e-11)(5.9722e24)(7.346e22) / (3.84e8)^2
≈ 2.9281e37 / 1.47456e17
≈ 1.99e20 N
So the gravitational force is about 1.99 × 10^20 newtons.
F = G m1 m2 / r^2
With G = 6.67430×10^−11 m^3 kg^−1 s^−2,
m1 = 5.9722×10^24 kg, m2 = 7.346×10^22 kg, r = 3.84×10^8 m:
F = (6.67430e-11)(5.9722e24)(7.346e22) / (3.84e8)^2
≈ 2.9281e37 / 1.47456e17
≈ 1.99e20 N
So the gravitational force is about 1.99 × 10^20 newtons.
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