Question

On a coordinate plane, a line goes through (negative 5, negative 4) and (0, negative 3). A point is at (negative 2, 2).
What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)?

y = One-fifthx + 4
y = One-fifthx + Twelve-fifths
y = –5x + 4
y = –5x + Twelve-fifths

Answer 1

y = One-fifthx + Twelve-fifths

Reason: slope = (−3 − (−4)) / (0 − (−5)) = 1/5. Using y = (1/5)x + b and (−2,2): 2 = (1/5)(−2) + b ⇒ b = 12/5.