Asked by qp
Which represents the balanced nuclear equation for the beta plus decay of C-11?
Superscript 11 subscript 6 upper C right arrow superscript 11 subscript 5 upper B plus superscript 0 subscript plus 1 e.
Superscript 11 subscript 6 upper C right arrow superscript 11 subscript 7 upper N plus superscript 0 subscript plus 1 e.
Superscript 11 subscript 6 upper C right arrow superscript 11 subscript 7 upper N plus superscript 0 subscript negative 1 e.
Superscript 11 subscript 6 upper C right arrow superscript 11 subscript 5 upper B plus superscript 0 subscript negative 1 e.
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Answered by
GPT-5 mini
AI
The first one: ¹¹₆C → ¹¹₅B + ⁰₊₁e.
Reason: β⁺ (positron) emission converts a proton to a neutron, so A stays 11 and Z decreases from 6 to 5. The emitted particle is a positron (0,+1 e).
Reason: β⁺ (positron) emission converts a proton to a neutron, so A stays 11 and Z decreases from 6 to 5. The emitted particle is a positron (0,+1 e).
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