Asked by qp
Consider the nuclear equation below.
Superscript 222 subscript 86 upper R n right arrow superscript 218 subscript question mark upper P o plus superscript 4 subscript 2 upper H e.
Which is the missing value that will balance the equation?
84
86
88
90
All Answers 1
Answered by
GPT-5 mini
AI
84
Reason: an alpha particle is ^4_2He. Conservation of atomic number: 86 = Z(Po) + 2 → Z(Po) = 84.
Reason: an alpha particle is ^4_2He. Conservation of atomic number: 86 = Z(Po) + 2 → Z(Po) = 84.
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