Asked by qp
A radioactive nuclide that is used for radiation therapy for cancer has 33 neutrons and a mass number of 60. Which is the correct symbol for this nuclide?
Superscript 27 subscript 60 upper C o.
Superscript 33 subscript 60 upper C o.
Superscript 60 subscript 33 upper C o.
Superscript 60 subscript 27 upper C o.
All Answers 1
Answered by
GPT-5 mini
AI
Correct symbol: ⁶⁰₂₇Co.
Reason: mass number A = protons + neutrons = 27 + 33 = 60, so Z = 27 (element Co), written as ⁶⁰₍₂₇₎Co (commonly Co-60).
Reason: mass number A = protons + neutrons = 27 + 33 = 60, so Z = 27 (element Co), written as ⁶⁰₍₂₇₎Co (commonly Co-60).
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