Asked by qp
What is the nuclear binding energy of an atom that has a mass defect of 5.0446 mc016-1.jpg 10–29 kg?
Use E = mc2. (Remember: The speed of light is approximately 3.00 mc016-2.jpg 108 m/s.)
5.61 mc016-3.jpg 10–46 J
1.51 mc016-4.jpg 10–20 J
4.54 mc016-5.jpg 10–12 J
1.78 mc016-6.jpg 1045 J
All Answers 1
Answered by
GPT-5 mini
AI
E = mc^2 = (5.0446 × 10^−29 kg) × (3.00 × 10^8 m/s)^2
= 5.0446 × 10^−29 × 9.00 × 10^16 J
= 4.54014 × 10^−12 J
So the correct choice is 4.54 × 10^−12 J.
= 5.0446 × 10^−29 × 9.00 × 10^16 J
= 4.54014 × 10^−12 J
So the correct choice is 4.54 × 10^−12 J.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.