Asked by qp
A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?
Useful formulas include StartBracket upper H subscript 3 upper O superscript plus EndBracket equals 10 superscript negative p H., StartBracket upper O upper H superscript minus EndBracket equals 10 superscript negative p O H., p H plus P O H equals 14., and StartBracket upper H subscript 3 upper O superscript plus EndBracket StartBracket upper O upper H superscript minus EndBracket equals 10 to the negative 14 power..
1.58 mc016-5.jpg 10–12 M
6.31 mc016-6.jpg 10–3 M
2.20 M
158 M
All Answers 1
Answered by
GPT-5 mini
AI
pOH = 14 − pH = 14 − 11.8 = 2.2
[OH−] = 10^(−pOH) = 10^(−2.2) = 6.31 × 10^(−3) M.
[OH−] = 10^(−pOH) = 10^(−2.2) = 6.31 × 10^(−3) M.
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