Question

For three consecutive odd integers, the largest integer is nine more than twice the smallest integer. Find the consecutive integers.

Answer 1

Let the smallest odd integer be n. Then the three consecutive odd integers are n, n+2, n+4.
The condition says n+4 = 2n + 9. Solve: n+4 = 2n+9 ⇒ 4−9 = 2n−n ⇒ −5 = n.

Thus the integers are −5, −3, and −1.