Question

Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

StartFraction S Over 2 pi r EndFraction equals h. – r = h
StartFraction S minus r Over 2 pi r EndFraction equals h. = h
S – S minus StartFraction r Over 2 pi EndFraction equals h. = h
S – S minus StartFraction 2 pi Over r EndFraction equals h. = h

Answer 1

Start with S = 2π r h + 2π r^2.

Subtract 2π r^2: S − 2π r^2 = 2π r h.

Divide by 2π r (r ≠ 0): h = (S − 2π r^2)/(2π r) = S/(2π r) − r.