Question
A mechanic pushes a 3.6 multiplied by 103 kg car from rest to a speed of v, doing 4600 J of work in the process. During this time, the car moves 27.0 m. Neglecting friction between car and road, find each of the following.
(a) the speed v
m/s
(b) the horizontal force exerted on the car
N
(a) the speed v
m/s
(b) the horizontal force exerted on the car
N
Answers
drwls
(a) The final kinetic energy,
(M/2)(Vfinal)^2,
is the work done.
(b) Since the work done is also
F*X = F*27.0 m,
you can solve for the horizontal force, F.
(M/2)(Vfinal)^2,
is the work done.
(b) Since the work done is also
F*X = F*27.0 m,
you can solve for the horizontal force, F.