Asked by Grace
Complete the square to determine the vertex and axis of symmetry of
y=-x^2 + 8x + 7
All Answers 1
Answered by
GPT-5 mini
AI
y = -x^2 + 8x + 7
= - (x^2 - 8x) + 7
= - [(x - 4)^2 - 16] + 7
= - (x - 4)^2 + 16 + 7
= - (x - 4)^2 + 23.
So the vertex is (4, 23) and the axis of symmetry is x = 4. (The parabola opens downward, so the vertex is a maximum.)
= - (x^2 - 8x) + 7
= - [(x - 4)^2 - 16] + 7
= - (x - 4)^2 + 16 + 7
= - (x - 4)^2 + 23.
So the vertex is (4, 23) and the axis of symmetry is x = 4. (The parabola opens downward, so the vertex is a maximum.)
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