A hockey puck sliding on a frozen lake comes to rest after traveling 265 m.

If its initial velocity is 4.2 m/s, what is its acceleration (assumed constant)?
Answer in units of m/s2.

2 answers

Vf^2 = Vo^2 + 2ad,
0^2 = (4.2)^2 + 2 * a * d,
0 = 17.64 + 530a,
530a = -17.64,
a = -17.64 / 530 = -0.0333 m/s^2.
A hockey puck sliding on a frozen lake comes
to rest after traveling 302 m.
If its initial velocity is 2.9 m/s, what is its
acceleration (assumed constant)?
Answer in units of m/s
2
.
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