Question

What ADDITIONAL information is needed to prove that △ABC≅△EDC
using SAS if point C is the midpoint of both BD¯¯¯¯¯¯¯¯ and AE¯¯¯¯¯¯¯¯



(1 point)
Responses

AB¯¯¯¯¯¯¯¯≅ ED¯¯¯¯¯¯¯¯
AB¯¯¯¯¯¯¯¯≅ ED¯¯¯¯¯¯¯¯

∠ACB≅∠ECD
∠ACB≅∠ECD

∠BAC≅∠DEC
∠BAC≅∠DEC

BD¯¯¯¯¯¯¯¯≅ DC¯¯¯¯¯¯¯¯
BD¯¯¯¯¯¯¯¯≅ DC¯¯¯¯¯¯¯¯

Answer 1

∠ACB ≅ ∠ECD

Reason: C being the midpoint of AE and BD gives AC = CE and BC = CD. With ∠ACB = ∠ECD, the two triangles have two sides and the included angle congruent, so △ABC ≅ △EDC by SAS.