Asked by huhhf3;q
A student creates a computational model of the energy changes experienced by a pendulum.
Time (s)
Angle (rad)
Angular Velocity (rad/s) |
Kinetic Energy (J)
Potential Energy (J)
Total Energy (J)
0.00
0.087
0.000
0.000
0.010
0.010
0.050
0.085
-0.085
0.001
0.018
0.010
0.100
0.079
-0.100
0.003
0.015
0.010
0.150
0.000
-0.238
0.007
0.012
0.010
0.200
0.055
-0.200
0.011
0.007
0.010
0.250
0.00e
-0.345
0.015
0.004
0.01e
0.300
0.021
-0.375
0.018
0.001
0.010
0.350
0.002
-0.388
0.010
0.000
0.010
0.400
-0.017
-0.379
0.018
0.001
0.012
0.450
-0.038
-0.353
0.018
0.003
0.010
0.500
-0.052
-0.309
0.012
0.007
0.01e
0.550
-0.068
-0.251
0.008
0.011
0.010
0.800
-0.077
-0.180
0.004
0.015
0.010
0.650
-0.084
-0.101
0.001
0.017
0.010
0.700
0.087
-0.018
0.000
0.010
0.010
0.750
-0.080
0.000
0.001
0.018
0.012
0.800
-0.080
0.151
0.003
0.016
0.010
0.850
-0.071
0.225
0.000
0.012
0.01e
0.000
-0.058
0.283
0.010
0.008
0.010
0.050
-0.042
0.200
0.014
0.004
0.010
1.000
-0.023
0.371
0.017
0.001
0.010
1.050
-0.008
0.308
0.010
0.000
0.010
1.100
0.014
0.382
0.018
0.000
0.01e
Which conclusion can be made?
(1 point)
As the potential energy increases, kinetic energy decreases. The total energy stays the same.
As the potential energy increases, kinetic energy increases. Total energy increases.
As the potential energy increases, kinetic energy decreases. Total energy increases.
As the potential energy increases, kinetic energy increases. Total energy remains the same.
All Answers 1
Answered by
GPT-5 mini
AI
As the potential energy increases, kinetic energy decreases. The total energy stays the same.
This shows energy is conserved: PE and KE trade off so their sum remains (approximately) constant.
This shows energy is conserved: PE and KE trade off so their sum remains (approximately) constant.
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