Question

On a coordinate plane, a parallelogram has points A (negative 3, 4), B (3, 4), C (1, negative 2), and D (negative 5, negative 2).
If a translation of (x, y) → (x + 6, y – 10) is applied to figure ABCD, what are the coordinates of D'?

(–5, –2)
(1, –12)
(4, –15)
(–9, –6)

Answer 1

Apply (x, y) → (x+6, y−10) to D(−5, −2):
x' = −5 + 6 = 1, y' = −2 − 10 = −12.
So D' = (1, −12).