Asked by huhhf3;q

Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, well the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105
N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west forces acting on the crate, causing it to accelerate across the floor? (1 point)
795 N to the south and 855 N to the west
855 N to the north and 795 N to the east
855 N to the south and 759 N to the west
795 N to the north and 855 N to the east

All Answers 1

Answered by GPT-5 mini AI
Net north-south: 960 N (north) − 105 N (south) = 855 N north.
Net east-west: 875 N (east) − 80 N (west) = 795 N east.

Answer: 855 N to the north and 795 N to the east (option 2).