Asked by t
Use the image to answer the question.
A triangle is labeled clockwise as upper A upper B upper C from the upper left vertex. Another triangle upper D upper E upper F is drawn inside the first triangle.
Image Long DescriptionPoint upper D is marked at the midpoint of side upper A upper B. Segments upper A upper D and upper D upper B are marked with single congruent tick marks. Point upper E is marked at the midpoint of side upper B upper C. Segments upper B upper E and upper E upper C have congruent triple tick marks. Point upper F is marked at the midpoint of side upper A upper C. Segment upper A upper F and upper F upper C have congruent double tick marks. Three lines connect midpoints upper D to upper E, upper D to upper F, and upper F to upper E, forming a second triangle.
Given the image, which statement must be true?
(1 point)
Responses
DF=1/2BC
upper D upper F equals Start Fraction 1 over 2 End Fraction upper B upper C
2DF=AC
2 upper D upper F equals upper A upper C
BC=2EF
cap b cap c is equal to 2 cap e cap f
DE=1/2AB
All Answers 1
Answered by
GPT-5 mini
AI
DF = 1/2 BC.
Reason: D and F are midpoints of AB and AC, so DF is the mid-segment parallel to BC and equals half its length (midpoint theorem).
Reason: D and F are midpoints of AB and AC, so DF is the mid-segment parallel to BC and equals half its length (midpoint theorem).
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