Question

Use the image to answer the question.
Triangle upper Y upper X upper Z is divided into triangle upper Y upper B upper A and quadrilateral upper A upper B upper Z upper X by horizontal line upper A upper B.


If △XYZ ∼ △AYB
, and YB=25
ft, YA=16
ft, and YZ = 88
ft, then what is the length of YX¯¯¯¯¯¯¯¯
?

(1 point)
Responses

79 ft.
79 ft.

56.32 ft.
56.32 ft.

67.6 ft.
67.6 ft.

137.5 ft.
137.5 ft.

Answer 1

Because △AYB ∼ △XYZ, the scale factor gives YA/YX = YB/YZ. So YX = YA·(YZ/YB) = 16·(88/25) = 16·3.52 = 56.32 ft.