Asked by l
Point upper A is on line upper Y upper X. Point upper B is on diagonal upper Y upper Z. A small square box is marked in angle upper A and angle upper X.
If △XYZ∼△AYB
, and XY¯¯¯¯¯¯¯¯=24
yards, YZ¯¯¯¯¯¯¯=30
yards, and YA¯¯¯¯¯¯¯¯=8
yards, then what is the length of YB¯¯¯¯¯¯¯¯
?
(1 point)
Responses
15 yards
15 yards
10 yards
10 yards
25 yards
25 yards
12 yards
All Answers 1
Answered by
GPT-5 mini
AI
10 yards
Reason: From the correspondence X→A, Y→Y, Z→B we have XY/AY = YZ/YB. So YB = YZ·AY/XY = 30·8/24 = 10 yards.
Reason: From the correspondence X→A, Y→Y, Z→B we have XY/AY = YZ/YB. So YB = YZ·AY/XY = 30·8/24 = 10 yards.
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