Asked by b
(a)
The time that it took students to complete an obstacle course in Gym class follows a normal distribution.
The mean time is 21 minutes with a standard deviation of 4 minutes.
Hint: Drawing and labeling a normal curve may help you to answer parts a - e.
Part A
What percent of the the students took between 13 and 29 minutes to complete the obstacle course?
A
68%
B
95%
C
99.7%
D
100%
(b)
Part B
What percent of students took more than 17 minutes to complete the obstacle course?
A
34%
B
68%
C
50%
D
84%
(c)
Part C
68% of students took between what two times to complete the obstacle course?
A
Between 9 minutes and 33 minutes
B
Between 13 minutes and 33 minutes
C
Between 17 minutes and 25 minutes
D
Between 17 minutes and 21 minutes
(d)
Part D
Emilio took 27 minutes to complete the course.
Find the z-score that corresponds to Emilio's time.
(e)
Part E
If Ashley's time to complete the obstacle course corresponds to a z-score of -1.2, how long did it take her to complete the course?
Enter your answer into the box below. Then use the drop-down menu to select the correct units.
All Answers 1
Answered by
GPT-5 mini
AI
Mean = 21, SD = 4.
(a) 13 to 29 is μ ± 2σ → 95% → B.
(b) 17 = μ − 1σ. Proportion > μ − 1σ ≈ 84% → D.
(c) 68% is μ ± 1σ → 21 ± 4 → between 17 and 25 minutes → C.
(d) z = (27 − 21)/4 = 6/4 = 1.5.
(e) x = μ + zσ = 21 + (−1.2)(4) = 21 − 4.8 = 16.2 minutes.
(a) 13 to 29 is μ ± 2σ → 95% → B.
(b) 17 = μ − 1σ. Proportion > μ − 1σ ≈ 84% → D.
(c) 68% is μ ± 1σ → 21 ± 4 → between 17 and 25 minutes → C.
(d) z = (27 − 21)/4 = 6/4 = 1.5.
(e) x = μ + zσ = 21 + (−1.2)(4) = 21 − 4.8 = 16.2 minutes.
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