Asked by unknown no more
lets say my grade is 86%.. Now, how many points would i need in order to raise it to an 89 or 90%? The test i want to correct has 12/16 points, or 75% of the test. my Final test is worth 25%. If i do corrections on the test with 75%, and i correct all the answers (correcting an answer only gives 1/2 of a point, so 0.5) AND i get all answers correct on that final test, what would my grade be?
what would my grade be if i got all test corrections RIGHT but i DIDN'T do final test yet?
All Answers 1
Answered by
GPT-5 mini
AI
Short answers up front:
- If you correct all 4 wrong answers on the 12/16 test you gain 2 points → test becomes 14/16 = 87.5% (was 75%).
- If your current overall is 86% (with the final still worth 25%) and you get 100% on the final but make no corrections, your course final = 0.75·86 + 0.25·100 = 89.5%.
- If you both make all corrections (test → 87.5%) and get 100% on the final, the course final depends on how much that 12/16 test is worth of the total course. See formulas and examples below.
Details and formula (so you can plug in the test weight):
- Test old = 12/16 = 75%. Test corrected = 14/16 = 87.5%. Delta on that test = 12.5 percentage points.
- Let t = the weight of that test as a percent of the TOTAL course grade (for example t = 10 means the test is worth 10% of the course). Let w_final = 25% (given).
- If your reported 86% already includes the 75%-worth of coursework done so far, then:
- New current course grade after corrections (before final) = 86 + (12.5)*(t/100) (adds the test’s change × its weight).
- Final course grade if you get F% on the final = (1 - w_final) * [new current grade] + w_final * F
= 0.75 * [86 + 12.5*(t/100)] + 0.25 * F.
Examples (useful common t values)
- If the test is worth 10% of the course (t = 10):
- After corrections (before final): 86 + 12.5*0.10 = 87.25%.
- If you then get 100% on the final: final course = 0.75*87.25 + 0.25*100 = 90.44% (≈ 90.4%).
- If the test is worth 5% (t = 5):
- After corrections: 86 + 12.5*0.05 = 86.625%.
- With 100 on final: 0.75*86.625 + 25 = 89.97% (≈ 90.0).
- If the test is worth 15% (t = 15):
- After corrections: 86 + 12.5*0.15 = 87.875%.
- With 100 on final: 0.75*87.875 + 25 = 90.91%.
How many points do you need on the final to reach 89 or 90?
- If you do no corrections (current = 86): required final score F solves 0.75*86 + 0.25*F = T.
- For T = 89 → F = 98%
- For T = 90 → F = 102% (impossible)
- If you do the corrections and the test weight is t (so new current = 86 + 12.5*(t/100)), required F = (T - 0.75*(86 + 12.5*(t/100))) / 0.25. (Plug in t to get the required final score.)
If you want exact answers for your situation, tell me:
1) Is the 86% your current course grade excluding the final? (I assumed yes above.)
2) How much of the total course grade is that 12/16 test worth (t%)?
With those two values I’ll give the exact numbers for (a) your grade after corrections (before the final) and (b) your final course grade if you get 100% on the final (and also the exact final needed to hit 89 or 90).
- If you correct all 4 wrong answers on the 12/16 test you gain 2 points → test becomes 14/16 = 87.5% (was 75%).
- If your current overall is 86% (with the final still worth 25%) and you get 100% on the final but make no corrections, your course final = 0.75·86 + 0.25·100 = 89.5%.
- If you both make all corrections (test → 87.5%) and get 100% on the final, the course final depends on how much that 12/16 test is worth of the total course. See formulas and examples below.
Details and formula (so you can plug in the test weight):
- Test old = 12/16 = 75%. Test corrected = 14/16 = 87.5%. Delta on that test = 12.5 percentage points.
- Let t = the weight of that test as a percent of the TOTAL course grade (for example t = 10 means the test is worth 10% of the course). Let w_final = 25% (given).
- If your reported 86% already includes the 75%-worth of coursework done so far, then:
- New current course grade after corrections (before final) = 86 + (12.5)*(t/100) (adds the test’s change × its weight).
- Final course grade if you get F% on the final = (1 - w_final) * [new current grade] + w_final * F
= 0.75 * [86 + 12.5*(t/100)] + 0.25 * F.
Examples (useful common t values)
- If the test is worth 10% of the course (t = 10):
- After corrections (before final): 86 + 12.5*0.10 = 87.25%.
- If you then get 100% on the final: final course = 0.75*87.25 + 0.25*100 = 90.44% (≈ 90.4%).
- If the test is worth 5% (t = 5):
- After corrections: 86 + 12.5*0.05 = 86.625%.
- With 100 on final: 0.75*86.625 + 25 = 89.97% (≈ 90.0).
- If the test is worth 15% (t = 15):
- After corrections: 86 + 12.5*0.15 = 87.875%.
- With 100 on final: 0.75*87.875 + 25 = 90.91%.
How many points do you need on the final to reach 89 or 90?
- If you do no corrections (current = 86): required final score F solves 0.75*86 + 0.25*F = T.
- For T = 89 → F = 98%
- For T = 90 → F = 102% (impossible)
- If you do the corrections and the test weight is t (so new current = 86 + 12.5*(t/100)), required F = (T - 0.75*(86 + 12.5*(t/100))) / 0.25. (Plug in t to get the required final score.)
If you want exact answers for your situation, tell me:
1) Is the 86% your current course grade excluding the final? (I assumed yes above.)
2) How much of the total course grade is that 12/16 test worth (t%)?
With those two values I’ll give the exact numbers for (a) your grade after corrections (before the final) and (b) your final course grade if you get 100% on the final (and also the exact final needed to hit 89 or 90).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.