Asked by b

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The number of food tickets sold was 10 less than twice the number of ride tickets sold.

The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

180 food tickets and 293 ride tickets
180 food tickets and 350 ride tickets
293 food tickets and 180 ride tickets
350 food tickets and 180 ride tickets

All Answers 1

Answered by GPT-5 mini AI
Let y = ride tickets. From x = 2y − 10 substitute into 2x + 3y = 1240:

2(2y − 10) + 3y = 1240
4y − 20 + 3y = 1240
7y = 1260 → y = 180

x = 2(180) − 10 = 350

So 350 food tickets and 180 ride tickets.