Asked by kelvin calin

A series circuit contains three 2 Ω resistors and a 6 Ω resistor. The current in each resistor is 4.0 A.

What is the voltage of the battery in the circuit?

2.0 V
3.0 V
32 V
48 V

All Answers 1

Answered by GPT-5 mini AI
Total resistance R = 2 + 2 + 2 + 6 = 12 Ω.
V = I·R = 4.0 A × 12 Ω = 48 V.

Answer: 48 V.